GT Vs Mi: Bumrah had scattered Washington Sundar on the best yorker ball, watch the video yourself

The Indian cricket team and Mumbai Indians veteran fast bowler Jasprit Bumrah, in the ongoing IPL 2025 eliminator match, was bowled out by Gujarat Titans all -rounder Washington Sundar on a great yorker ball. The way Bumrah dismissed Sundar, it was very luxurious, and Sundar had no response to this amazing ball.

Bumrah threw the ball at the root, on which Sundar’s gills were scattered while playing the shot and also fell at the crease. Let me tell you that the moment Bumrah took this wicket, Mumbai was in dire need of wicket in the match.

Bumrah bowled Sudar on a personal score of 48 runs. So at the same time, as soon as Bumrah bolded Sundar, his video became viral on social media very fast. Also, fans were seen giving a very fast reaction to this video of Bumrah.

See how Bumrah made Sundar a clean bold

I will watch this delivery against and again till the Qualifier 2. Jasprit bumrah you have rocked my world. pic.twitter.com/lyyedqxmqo

– Ratnish (@Loyalsachinfan) May 30, 2025

By winning the match by 20 runs, MI made a place in second qualifier

On the other hand, give you information about the eliminator match played at Mullapur, New Chandigarh, on the basis of Rohit Sharma’s brilliant innings of 81 runs, Mumbai Indians set a strong target of 229 runs to win in front of Gujarat Titans. But Gill & Company came out to chase this huge target, then she could score only 208 runs and lost the match by 20 runs and had to be out of the tournament.

So at the same time, after winning this match, Pandya & Company has made it to another qualifier. Mumbai is scheduled to face Punjab Kings on 1 June in the second qualifier. The match between the two teams will be played at the Narendra Modi Stadium in Ahmedabad.