Spinner Krunal Pandya performed brilliantly for RCB
IPL 2025, Mi vs RCB: The 20th match was played between Mumbai Indians and Royal Challengers Bangalore in IPL today, 7 April, Monday. In this match played at the historic Wankhede Stadium, RCB won by 12 runs against Mumbai.
Batting first in the match, RCB had set a target of 222 runs to win in front of MI, chasing Mumbai to score only 209 runs, and in the match she had to face defeat by a close margin of 12 runs. Also, let us know that this is RCB’s first win against Mumbai in Wankhede after 2015.
Mi vs RCB, IPL 2025’s 20th match condition
Royal Challengers Bangalore scored a total of 221 at the loss of five wickets in the prescribed 20 overs, batting first after losing the toss to you in detail about the match. For RCB, Virat Kohli scored 67 and Devdutt Padikkal scored 37 runs, while Rajat Patidar scored a brilliant captaincy innings of 64 runs in 32 balls with the help of five and four sixes.
Apart from this, in the end, wicketkeeper Jitesh Sharma remained unbeaten after scoring 40*. So at the same time, when we talk about the bowling of Mumbai Indians, Trent Bolt and Hardik Pandya got 2-2 wickets. Apart from this, young spinner Vignesh Puthur got 1 wicket.
Subsequently, when Mumbai Indians came out to chase the target of 222 runs from RCB, she was able to score a total of 209 runs in 20 overs at the loss of 9 wickets. For MI, Tilak Verma scored 56 and Hardik Pandya played a stormy innings of 42 runs in 15 balls with the help of 3 fours and 4 sixes, but he could not win his team.
In the last over of the innings, MI needed 19 runs to win, but spinner Krunal Pandya played an important role in winning the team by dismissing Mitchell Santner (8), Deepak Chahar and Naman Dhir (11) in this over.
Krunal Aura Pandya. pic.twitter.com/7wvnbitlo
– Royal Challengers Bengaluru (@Rcbtweets) April 7, 2025
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