Mi vs SRH: Hyderabad aims for 163 runs against Mumbai, see first innings

Delhi: The Indian Premier League (IPL) teams of Mumbai Indians (Mi) and Sunrisers Hyderabad (SRH) are face to face in the 33rd match of 2025. This match is being played at the Wankhede Stadium in Mumbai. Mumbai Indians captain Hardik Pandya won the toss and decided to bowl first and invited Sunrisers Hyderabad to bat first. Batting first, Sunrisers Hyderabad scored 162 runs at the loss of 5 wickets in 20 overs. Now Mumbai needs 163 runs to win this match.

Abhishek Sharma played stormy innings

SRH opener Abhishek Sharma made a tremendous start. He played a fast innings of 40 runs in just 28 balls which included 7 fours and 1 six. However, he was caught out of Hardik Pandya in the 8th over.

Travis Head and Klassen scored useful runs

The second opener Travis Head scored 29 runs in 28 balls, but he could not make his innings big and became a victim of Will Jacks. At the same time, wicketkeeper Henrik Klassen once again scored 37 runs in 28 balls while batting brilliantly and brought the team to a strong position. In the end overs, Aniket Verma played a fast innings of 18 runs in 8 balls, while captain Pat Cummins returned unbeaten after scoring 8 runs in 4 balls.

Mumbai bowlers did good work

The bowlers of Mumbai Indians bowled tightly. Hardik Pandya took 1 wicket for 42 runs in 4 overs, while Will Jacks and Trent Bolt also got 1-1 wickets. Jasprit Bumrah was the most economical and took 1 wicket for just 21 runs in 4 overs.

Now Mumbai needs 163 runs to win

The Hyderabad team has so far scored an average score, but Mumbai Indians have a strong batting lineup. It will be interesting to see if SRH bowlers will be able to defend this score or Mumbai Indians will easily win.

Playing XI of both teams

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